Answer:
The equation of a line parallel to the line and passing through (1, -1) is:
Step-by-step explanation:
Given the line
y = -3
We know that the slope-intercept form of the line equation is
[tex]y=mx+b[/tex]
where m is the slope and b is the y-intercept
Thus, the slope of the equation y=-3 will be m = -3
We know that the parallel lines have the same slopes.
Thus, the slope of the parallel line will also be -3.
Thus, using the point-slope form to find the line equation is
[tex]y-y_1=m\left(x-x_1\right)[/tex]
substituting the values m = -3 and the point (1, -1)
y-(-1) = -3(x-1)
y+1 = -3x+3
y=-3x+3-1
y=-3x+2
Thus, the equation of a line parallel to line and passing through (1, -1) is:
