Answer:
[tex]c=0.2\ J/g^{\circ} C[/tex]
Explanation:
Given that,
Mass of a glass, m = 4 g
Initial temperature, [tex]T_i=5^{\circ} C[/tex]
Final temperature, [tex]T_f=45^{\circ} C[/tex]
Heat absorbed, Q = 32 J
We need to find the specific heat of the glass. The formula for the heat absorbed is given by :
[tex]Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{32\ J}{4\ g\times (45-5)^{\circ} C}\\\\=0.2\ J/g^{\circ} C[/tex]
So, the required specific heat of the glass is [tex]0.2\ J/g^{\circ} C[/tex].
