Respuesta :

Answer:

[tex]2 \cos ^{2} (4x) - 1 = 0 \\ \cos ^{2} (4x) = \frac{1}{2} \\ \cos(4x) = \sqrt{ \frac{1}{2} } \\ 4x = { \cos }^{ - 1} ( \sqrt{ \frac{1}{2} } ) \\ x = \frac{ { \cos}^{ - 1} ( \sqrt{ \frac{1}{2} } )}{4} \\ x \isnt \: \frac{\pi}{2} [/tex]