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Consider the production of sulfur trioxide from sulfur dioxide and oxygen gas:How many grams of sulfur dioxide reacted if 163 kilojoules of heat were evolved in an experiment

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Answer:

102.4 g

Explanation:

The equation of the reaction is;

2SO2(g) + O2(g) -----> 2SO3(g) --------ΔH = -198 KJ/mol

Now, given that;

If 2 moles of SO2 evolves 198 KJ/mol of heat

x moles of SO2 evolves 163 KJ/mol of heat

x = 2 * 163/198

x = 1.6 moles of SO2

molar mass of SO2 = 64 g/mol

mass of SO2 = 1.6 moles * 64 g/mol = 102.4 g

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