Given that,
Mass of particle 1, m₁ = 2.58 g = 0.00258 kg
Speed of particle 1, v₁ = 2.51 m/s
Mass of particle 2, m₂ = 6.53 g = 0.00653 kg
Speed of particle 2 = 0 (at rest)
To find,
The speed of centre of mass of the two particles.
Solution,
The formula for the centre of mass of the system is givn by :
[tex]V_{cm}=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}\\\\V_{cm}=\dfrac{0.00258 \times 2.51+0.00653 \times 0}{0.00258 +0.00653 }\\\\=0.71\ m/s[/tex]
So, the speed of the centre of mass is 0.71 m/s.
