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Eva will draw two marbles from a bag that contains 5 red marbles, 7 blue marbles, 6 green marbles, and 2 yellow marbles. If Eva is going to reach in the bag without looking, what is the probability that she will draw a yellow marble on the first try without replacing and draw a red marble on the second try?

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chrisbot618

Answer:7 in 21

Step-by-step explanation:

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MARKMEBRAINLIESTPLS

Answer: THE PROBABILITY OF DRAWING A YELLOW MARBLE IS 1/10

THE PROBABILITY OF DRAWING A RED MARBLE IS 5/18

Step-by-step explanation:

FIRST WE DIVIDE THE NUMBER OF YELLOW MARBLES  WITH THE TOTAL AMOUNT OF MARBLE THAT IS 2(THE NUMBER OF YELLOW MARBLES)/20(THE TOTAL NUMBER OF MARBLES IN THE BAG)

SO 2/20=1/10

WHEREAS IN THE SECOND ONE, THE YELLOW MARBLES ARE ALREADY DRAWN SO 20-2=18 5(THE NUMBER OF RED MARBLES)/18(THE TOTAL NUMBER OF MARBLES)

SO 5/18

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