Respuesta :
Answer:
0.31 L
General Formulas and Concepts:
Math
Pre-Algebra
- Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
Chemistry
Atomic Structure
- Moles
Aqueous Solutions
- Molarity = moles of solute / liters of solution
Equilibrium - Acid/Base
- Strong Acids
- Weak Acids
- Writing Acids
Explanation:
Step 1: Define
[Given] 3.5 M HCl
[Given] 1.1 moles
[Solve] Liters solution
Step 2: Solve
- Substitute in variables [Molarity]: [tex]\displaystyle 3.5 \ M = \frac{1.1 \ moles}{x \ L}[/tex]
- [Solution] Cross-Multiply [Equality Property]: [tex]\displaystyle x \ L = \frac{1.1 \ mol}{3.5 \ M}[/tex]
- [Solution] Divide: [tex]\displaystyle x = 0.314286 \ L[/tex]
Step 3: Check
Follow sig fig rules and round. We are given 2 sig figs.
0.314286 L ≈ 0.31 L