Given: ABC , BD is an
altitude to side AC, & D is a midpoint
Prove: AB BC

Answer:
steps below
Step-by-step explanation:
BD⊥AC ∠ADB = ∠CDB = 90°
D is mid-point: AD = CD
BD = BD
ΔADB ≅ ΔCDB
AB = BC
Answer:
Step-by-step explanation:
BD is an altitude given
D is midpoint of AC given
BD ⊥ AC an altitude is a perpendicular segment
from a vertex to the opposite side
AD = DC because BD is a perpendicular bisector
BD = BD reflexive property
∠ADB ≅ ∠CDB because BD ⊥ AC
ΔADB ≅ ΔCDB SAS
AB ≅BC corresponding sides of congruent triangles
are congruent