Respuesta :
180 K
V1/T1 = V2/T2
V1 = 500 mL
T1 = 300 K
V2 = 300 mL
Solve the equation for T2 —> T2 = V2T1/V1
T2 = (300 mL)(300 K) / (500 mL) = 180 K
V1/T1 = V2/T2
V1 = 500 mL
T1 = 300 K
V2 = 300 mL
Solve the equation for T2 —> T2 = V2T1/V1
T2 = (300 mL)(300 K) / (500 mL) = 180 K
The temperature should be lowered to 300K to bring the volume to 300mL.
What is temperature?
Temperature is the degree of hotness or coldness of a place or a body. The SI unit of temperature is Kelvin.
What is volume?
Volume is the amount of space occupied by matter. The SI unit of volume is cubic metre.
Using Charles law,
V1/V2 = T1/T2
Where, V1 and T1 are the initial volume and temperature
Similarly, V₂ and T₂ are the final volume and temperature.
Given:
V1 = 500mL
T1 = 300K
V2 = 300mL
T2 = ?
V1T2/V1 = V2T1/V1
T2 = V2T1/V1
= 300mL x 300K/500mL
T2 = 180K
Hence, the temperature should be lowered to 300K to bring the volume to 300mL.
To learn more about temperature and volume here
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