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If Darian contains 3.25 moles of gas in a container with a volume of 60.5 liters and at a temperature of 400 K, what is the pressure inside the container?
PV = nRT


with atm: R = 0.0821 L*atm/(K*mol) with kPa: R =8.31 L*kPa /(K*mole)

Respuesta :

samueladesida43

Answer:

1.76atm

Explanation:

Using the ideal gas law equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question,

P = ?

V = 60.5 liters

n = 3.25 moles

T = 400 K

R = 0.0821 Latm/molK

Using PV = nRT

P = nRT/V

P = (3.25 × 0.0821 × 400) ÷ 60.5

P = 106.73 ÷ 60.5

P = 1.76atm

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