Answer: 480 mL, 600 mL
Step-by-step explanation:
Given
The concentration of the first acid is 75%
The concentration of the second acid is 30%
The final mixture has a concentration of 50%
The final volume is 1080 mL
Suppose x and y be the volume of the first and second acid
[tex]\therefore x+y=1080\quad \ldots(i)\\0.75x+0.3y=0.5\times 1080\quad \ldots(ii)[/tex]
Solving the above equations we get
[tex]x=480,y=600[/tex]
So, the quantity of the first acid is 480 mL and 600 mL for the second mixture.
