Respuesta :

there is a right triangle in a cone :)

we will use pythagorean theorem ;

?^2+(7.41)^2=16^2

?^2=16^2-(7.4)^2

if we both side square root;

[tex] \sqrt{?^2}= \sqrt{16^2-(7.4)^2} \\ ?= \sqrt{16^2-(7.4)^2}[/tex]

So the answer is 4th option :)

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