Answer:a)No of moles of Aluminium=0.4703
b)number of aluminum atoms=2.832 x 10^23 atoms
Explanation:
a)Given that The Amount/ Mass of Aluminum is 12.69g
We know that
No of moles =Mass/ Molar mass
Molar mass of Aluminium, Al is 26.982 g/mol
No of moles =12.69g/26.982 g/mol
No of moles =0.4703
Also
b) 1 mole of aluminium must contain 6.022 x 10^23 atoms of aluminium
which is known as Avogadro's constant.
Therefore, 0.4703 moles will contain 0.4703 x 6.022 x 10^23 atoms =2.832 x 10^23 atoms
