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In a solution containing 21.2 g sodium carbonate in 1.50 L of solution, calculate
the concentration of the sodium and carbonate ions.

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Answer:

0.13 molL-1

Explanation:

We must first obtain the number of moles of sodium carbonate as follows;

Number of moles = mass/molar mass

Number of moles = 21.2 g/106 g/mol

Number of moles= 0.2 moles

Number of moles = concentration × volume

Volume = 1.50 L

Concentration = number of moles/volume

Concentration = 0.2 moles/1.5 L

Concentration = 0.13 molL-1

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