Answer:
1178J is the heat of the reaction
Explanation:
Assume that the reaction mixture has a density of 1.00 g/mL and a specific heat of 4.184 J/g-oC. The calorimeter has a heat capacity of 10.0 J/oC
The heat of a reaction follows the equation:
Q = m*S*ΔT
Where Q is the heat of the reaction,
m is the mass:
61.2mL * (1.00g/mL) = 61.2g
S is specific heat = 4.184J/g°C
ΔT = 4.6°C
Replacing:
Q = 61.2g*4.184J/g°C*4.6°C
Q = 1178J is the heat of the reaction
