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A 25.0mL sample of 2.0mol/L sodium oxalate is reacted with 30.0mL of 1.50 mol/L copper (II) nitrate solution a student recovers 5.82 grams of precipitate when they perform the reaction.

Write a balenced chemical reaction.

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Answer:

Na2C2O4(aq) + Cu(NO3)2(aq) → 2NaNO3(aq) + CuC2O4(s)

Explanation:

Sodium oxalate, Na2C2O4 reacts with copper (II) nitrate, Cu(NO3)2 producing an insoluble salt. As the reaction is of 2 salts you can know there is an ion exchange reaction where sodium nitrate is produced ans copper (II) oxalate (This salt is the precipitate). The reaction is:

Na2C2O4(aq) + Cu(NO3)2(aq) → 2NaNO3(aq) + CuC2O4(s)

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