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A chemical reaction occurring in a cylinder equipped with a moveable piston produces 0.601 mol of a gaseous product. If the cylinder contained 0.300 mol of gas before the reaction and had an initial volume of 2.16 L, what was its volume after the reaction

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Answer:

4.33 L

Explanation:

Assuming ideal behaviour and that all 0.300 moles of gas reacted, we can solve this problem using Avogadro's law, which states that at constant temperature and pressure:

  • V₁n₂ = V₂n₁

Where in this case:

  • V₁ = 2.16 L
  • n₂ = 0.601 mol
  • V₂ = ?
  • n₁ = 0.300 mol

We input the given data:

  • 2.16 L * 0.601 mol = V₂ * 0.300 mol

And solve for V₂:

  • V₂ = 4.33 L

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