PART A: Rosie writes the equation 24(mx+n)=3x+17, where m and n are real numbers.
If m=14 and n=13, does the equation have one solution, infinitely many solutions, or no solutions? Explain your answer.

PART B: If m=18, what must be the value of n for the equation to have infinitely many solutions? Explain your answer.

Respuesta :

Answer:

PART A:

[tex]24(mx + n) = 3x + 17[/tex]

when m is 14 and n is 13:

[tex]24 \{(14)x + 13) = 3x + 17 \\ 24(14x + 13) = 3x + 17 \\ 336x + 312 = 3x + 17[/tex]

collect like terms:

[tex]336x - 3x = 17 - 312 \\ 333x = - 295 \\ x = - 0.886 \\ \\ { \boxed{ \boxed{ \sf{it \: has \: one \: solution}}}}[/tex]

PART B:

[tex]if \: m \: is \: 18 \\ 24(18x + n) = 3x + 17 \\ [/tex]

remember x is -0.886

[tex]24 \{(18 \times - 0.886) + n \} = (3 \times - 0.886) + 17 \\ - 382.752 + 24n = - 26.58 \\ 24n = 356.172 \\ { \boxed{ \boxed{ \sf{n \: is \: 14.8}}}}[/tex]

  • The given equation has  one solution at x = 0.886 .
  • Equation have infinitely many solution when n = -15.41 .

Given equation;

24( mx + n ) = 3x + 17

where m and n are real numbers.

  • Part 1 ;   If m = 14 and n = 13;

Putting the value of m and n in the given equation.

= 24( 14.x + 13 ) = 3x + 17

=  336x + 312 = 3x + 17

=  336x - 3x = 17- 312

=  333x = -295

=   x = [tex]\frac{-295}{333}[/tex]

=   x = 0.886

Thus x = 0.886 we can say that the equation having one solution .

A linear equation in one variable is an equation which has a maximum of one variable of order 1. It is of the form ax + b = 0, where x is the variable. This equation has only one solution.

  • part 2 ;  if m = 18 then find n .

put m = 18 in the given equation

= 24(18.(0.886) + n ) = 3(0.886) + 17

= 24(15.94) + 24n = 2.658 + 17

= 382.56 + 24n = 19.658

= 24n = 19.658 - 382.56

= n = [tex]\frac{-362.97}{24}[/tex]

= n = -15.41

The equation have infinitely many solution when n = -15.41.

For more details about the types of solution click the click given below.

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