Respuesta :

Answer:

  • -(s + 5)(j + 6)

Step-by-step explanation:

It seems a factoring problem:

  • -30 - js - 6s - 5j =
  • (-30 - 6s) - (js + 5j) =
  • -6(s + 5) - j(s + 5) =
  • (s + 5)( -6 - j) =
  • -(s + 5)(j + 6)

[tex]\bf{-(s+5)(j+6) }[/tex]

Step-by-step explanation:

[tex]-30-js-6s-5j\\\\(-30-6s)-js-5j\\\\(-30-6s)-(js+5j)\\\\-6(5+s)-j(s+5)\\\\(s+5)(-6-j)\\\\-(s+5)(j+6)[/tex]