The line passing through which two points is perpendicular to the line 10x + 2y = 2

A (-2,-7) and (1,8)
B (-5,5) and (0,4)
C ( 0,-9) and (5,-8)
D (-4,12) and (-2,2)
E (-2,11) and (1,-4)

Respuesta :

Answer:

[tex]10x + 2y = 2 \\ 2y = - 10x + 2 \\ y = - 5x + 1 \\ \perp \: l \rightarrow\: m = \frac{1}{5} \\ \frac{8 + 7}{1 + 2} = \frac{15}{3} = 5 \\ \frac{4 - 5}{0 + 5} = - \frac{1}{5} \\ \frac{ - 8 + 9}{5 - 0} = \color{yellow} \frac{1}{5} \: [/tex]

so the answer is C

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