Answer:
John is correct
Step-by-step explanation:
Let's solve the inequality:
[tex]3x-5\geq28[/tex]
[tex]3x\geq33[/tex]
[tex]x\geq11[/tex]
As we can see, the value of x can be either 11 or anything greater than 11. Since 12 is included in that solution set, John is correct.
wait
Step-by-step explanation:
ignore what I just said I was on crack bro
