Answer:
Below in bold
Step-by-step explanation:
I AM ASSUMING that CDEF is a Rhombus.
If it is than triangle DEG is right-angled.
so 2x + 18 + 5x + 2 = 90.
7x = 90 - 20 = 70
x = 7.
So m < CDF = 5x + 2
= 5(10) + 2
= 52 degrees.
m < DCE = 2(10) + 18 = 38 degrees.
The diagonal bisects < DCF so m < ECF = 38 degrees.
So m < DCF = 2 * 38 = 76 degrees.
Opposite angles of a rhombus are equal so m < DEF = 76 degrees.
