frankdawgg1400
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A ball is thrown into the air with a velocity of 33 ft/s. Its height, in feet, after t seconds is given by
s(t) = 33t − 16t2.
Find the velocity (in ft/s) of the ball at time
t = 1 second.

Respuesta :

mhomo

Answer:

velocity at t=1 is 1 ft/s

Step-by-step explanation:

by integration s(t) equation we get v(t)

v(t)=33-32t

by substitution t=1 in v(t) equation we get

33-32=1 ft/s

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