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What is the stretch when you pull with a force of 25 N on a spring with a spring constant of 8 N/m? *
0.06 m
1.28 m
3.13 m
0.12 m

Respuesta :

indrawboy

Hooke's Law

[tex]\tt F=k.\Delta x[/tex]

k = spring constant

x = stretch

F = force

Input the value

[tex]\tt \Delta x=\dfrac{F}{k}=\dfrac{25}{8}=3.125\rightarrow 3.13\:m[/tex]

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