[tex](4 + \frac{7}{4})( \frac{1}{8} - \frac{7}{8} ) \\ ( \frac{(4 \times 4) + 7}{4} )( \frac{1 - 7}{8} ) \\ ( \frac{16 + 7}{4})( \frac{ - 6}{8} ) \\ (\frac{23}{4} )( \frac{ - 6}{8} ) \\ \frac{23 \times ( - 6)}{4 \times 8} = \frac{ - 138}{32} [/tex]
