contestada

4. The 50-kg crate shown in Fig. rests on a horizontal surface for which the coefficient of
kinetic friction is u - 0.3. If the crate is subjected to a 400-N towing force as shown,
determine the acceleration of the crate.
your
P = 400 N
490.5 N
400 N
too

30
30°
+
F-0.3 Nc
Nc
ΣΕ = max
Σ F, = may
A. a = 4. 185 m/s2
B. a = 5. 185 m/s2
C. a = 6. 185 m/s2
D. The entire above are false

Respuesta :

Answer:

5.057 m/s^2

Explanation:

Force of kinetic friction = .3  = F /normal force

  .3 = F /(50* 9.81)     F of friction = 147.15

Net force =   400 - 147.5  =  252.85  N

F = m * a

252.85 = 50 * a       a = 5.057 m/s^2

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