danielsprecious537 danielsprecious537

09-05-2022
Physics

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The interior of a submarine located at a depth of 45 meters is maintained at normal atmospheric conditions. Find the total force exerted on a 20 cm by 20 cm square window

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09-05-2022

Answer:

P = ρ g H pressure due to 45 m of water

P = 1000 kg/m^3 * 9.8 m/s^2 * 45 m^2 = 4.41E5 kg/s^2

P = 4.41E5 N/m^2 pressure in excess of atmosphere at surface

F = P * A = 4.41E5 N/m^2 * 1/5 m * 1/5 m = 17,160 N/m^2

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