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W7L5 Stoichiometry Practice 2
WESOME
1. N2 + 3H2 → 2 NH3
If 2.7 grams of NH3 are produced, how many moles of Nitrogen gas were
used?

Respuesta :

Answer:

.079 moles of Nirogen gas (N2)

Explanation:

You can see from the equaton that each ONE mole of N2 produces TWO moles of NH3.

 Find the number of moles of NH3 produced.

    Using Periodic Table : Mole wt of NH3 = 17 gm/mole

          2.7 gm / 17 gm/mole = .1588 moles

      One half as many moles of N2 are needed  = .079 moles

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