missd894 missd894
  • 10-06-2022
  • Mathematics
contestada

find the quadratic equation whose roots are "-2" and 7

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loneguy
loneguy loneguy
  • 10-06-2022

Answer:

[tex]x^2 -5x-14=0[/tex]

Step-by-step explanation:

[tex]\text{Given that, the roots are}~ \alpha = -2~ \text{and}~ \beta = 7.\\\\\text{The quadratic equation with roots}~ \alpha~ \text{and}~ \beta ~ \text{is,} \\\\~~~~~~~x^2 - \left(\alpha + \beta \right)x + \alpha \beta =0 \\\\\implies x^2 -(-2+7)x + (-2)(7) = 0\\\\\implies x^2 -5x-14=0[/tex]

Answer Link
meredith48034
meredith48034 meredith48034
  • 10-06-2022

Answer:

Step-by-step explanation:

the quadratic equation is:

(x + 2)(x - 7)= 0

x^2 - 7x + 2x - 14

x^2 - 5x - 14

y = x^2 - 5x - 14

Answer Link

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