a 20 ml sample of gastric juice (composed of strong acid) was titrated with 0.0011 m aqueous naoh. the addition of 6.7 ml of naoh resulted in a neutral ph. what was the original ph of the gastric juice sample?

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08-11-2022
Chemistry

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a 20 ml sample of gastric juice (composed of strong acid) was titrated with 0.0011 m aqueous naoh. the addition of 6.7 ml of naoh resulted in a neutral ph. what was the original ph of the gastric juice sample?

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Bhuvangarg Bhuvangarg · Answer 1 · 2022-11-13T16:23:58+01:00

The original pH of the gastric juice sample is 3.43

What is pH ?

pH serves as a measure to calculate the acidity/alkalinity of a solution. It's ranges is between 0 - 14, with 7 being neutral. A pH below 7 indicates acidity and a pH above 7 indicates basicity. pH is actually a measure of the relative amounts of free hydrogen and hydroxyl ions in water.

As we know:

M₁V₁ = M₂V₂

For the given question:

M₁ = Concentration of gastric juice

V₁ = Volume of gastric juice (20 ml)

M₂ = Concentration of NaOH (0.0011 M)

V₂ = Volume of NaOH (6.7 ml)

So, M₁ = M₂V₂ / V₁

M₁ = 0.0011 × 6.7/20

M₁ = 0.000365

For pH:

pH = -log [H⁺]

pH = -log [0.000365]

pH = 3.43

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