The amount of 0.100 M HCl that 400 mg of Tumsr can neutralize, measured in mL, is 32 mL.
Chemical A chemical reaction's reactants and products are studied quantitatively in stoichiometry. The Greek words "stoikhein" (which means element) and "metron" (which means measure) are the roots of the English word "stoichiometry."
CaCO3 makes up 40 percent of Tumsr. As a result, 400 mg of Tumsr will have
400 x 40/100 = 160 mg CaCO3
According to the reaction's equation:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂(carbondioxide)
Mole ratio = 1:2
Mole of CaCO₃ = 0.16g/100 = 0.0016 moles
Equivalent mole of HCl = 0.0016 x 2 = 0.0032 moles
Volume of 0.0032 mole= 0.0032/0.1
Volume of 0.0032 mole = 32 ml.
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