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Find a polynomial function of least degree having only real​ coefficients, a leading coefficient of​ 1, and roots of 1- square root of 3 ​, and 6-i.

Respuesta :

The polynomial function is P(x) = x⁴ - 14x³ + 59x² - 50x - 74

What is a polynomial?

A polynomial is a function in which the least power of the unknown is 2.

What is the root of a polynomial?

The root of a polynomial is the value of the unknown which makes the polynomial equal zero.

How to find the polynomial of least degree having real coefficients?

Since we have that the given polynomial has roots 1 - √3 and 6 - i.

We also know that their conjugates 1 + √3 and 6 + i are also roots of the polynomial.

So, the factors of the polynomial are

  • x - (1 - √3) = (x - 1) + √3
  • x - (1 + √3) = (x - 1) + √3
  • x - (6 - i) = (x - 6) + i and
  • x - (6 + i) = (x - 6) - i

So, the required polynomial is P(x) = [(x - 1) + √3][(x - 1) - √3][(x - 6) + i][(x - 6) - i]

= [(x - 1)² - (√3)²][(x - 6)² - i²]    (Since a² - b² = (a - b)(a + b))

= [(x - 1)² - 3][(x - 6)² - (- 1)]

= [(x - 1)² - 3][(x - 6)² + 1]

Expanding the brackets, we have

= [x² - 2x + 1 - 3][(x² - 12x + 36 + 1]

= [x² - 2x - 2][(x² - 12x + 37]

= x⁴ - 12x³ + 37x² - 2x³ + 24x² - 74x - 2x² + 24x - 74

Collecting like terms, we have

= x⁴ - 14x³ + 59x² - 50x - 74

So, the polynomial is P(x) = x⁴ - 14x³ + 59x² - 50x - 74

Learn more about polynomial here:

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