The maximum height the object reaches is [tex]\frac{v^{2} sin^{2}x}{2g}[/tex].
When a particle is hurled obliquely near the surface of the earth, it travels along a curved route while accelerating continuously in the direction of the planet's centre (we assume the particle stays close to the surface of the globe). Such a particle's motion is known as projectile motion, and its route is referred to as a projectile. When a particle is sent into the air at a certain speed, the only force acting on it is the acceleration caused by gravity (g). This downward vertical acceleration has an effect. The fact that there is no acceleration in the horizontal direction indicates that the particle's horizontal velocity stays constant.
The highest vertical location along the object's flight is considered to be its greatest height. The range of the bullet is defined as its horizontal displacement. The starting velocity of the item affects the projectile's range.If v is the starting speed, g is the gravitational acceleration, and H is the highest point that may be reached in metres, then is the beginning speed's angle from the horizontal plane (radians or degrees).
The following formula determines the projectile's maximum height:[tex]\frac{v^{2} sin^{2}x}{2g}[/tex]
Here x is the angle.
this can be derived using the equation v^2 = u^2 - 2as where v = 0 m/s and u = usinx.
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