when solid sodium hydroxide dissolves in water, the δh for the solution process is −44.4 kj/mol. if a 13.9 g sample of naoh dissolves in 250.0 g of water in a coffee-cup calorimeter initially at 23.0 °c. what is the final temperature of the solution? assume that the solution has the same specific heat as liquid water, i.e., 4.18 j/g·k.

Respuesta :

The final temperature of solid sodium hydroxide dissolves in water is 355.88 kelvin.

A given amount of matter's heat capacity is the amount of energy needed to raise its temperature by one degree Celsius. While the heat capacity of 1 mole of a substance is known as its molar heat capacity, the heat capacity of 1 gram of a substance is referred to as its specific heat capacity (or specific heat). The equation q = mcT, where m is the mass of the sample, c is the specific heat, and T is the temperature change, can be used to determine how much heat is gained or lost by a sample (q).

Given

Mass of NaOH = 13.9 g

Mass of water = 250 gram

Specific heat of the solution = 4.18 j/g·k

Initial temperature  = 23.0 °c or 296 kelvin

Heat evolved in process = −44.4 kj/mol

Q = mc (T₂ - T₁)

−44400 j/mol = 263.9 x 4.18 j/g·k x (T₂ - 296k)

T₂ = 355.88 k

Hence, final temperature of NaOH solution is 355.88 kelvin.

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