Respuesta :
Entropy (S) for H₂(g) + F₂(g) ⇒2HF(g) would be less than zero. for 2NOBr(g )⇒2NO(g) + Br₂(g)would be greater than zero. for 2HBr(g) + Cl₂(g) ⇒ 2HCl(g) + Br₂(g) would be too close to zero to decide. for 4HCl(g) + O₂(g) ⇒ 2H₂O(g) + 2Cl₂(g) too close to zero to decide. for CaCO₂(s) ⇒ CaO(s) + CO₂(g)would be greater than zero.
Entropy is typically higher in reactions that entail the transformation of a solid into a liquid or a liquid into a gas.
Entropy is typically lower in reactions involving the transformation of gases into liquids and liquids into solids.
- H₂(g) + F₂(g) ⇒2HF(g)
Due to the fact that the total number of products generated decreased from 2 gases to 1, there was less degree of disorderliness, making this value less than zero.
- 2NOBr(g⇒ 2NO(g) + Br₂(g)
Due to the formation of two products from one, this is more than zero. The number of gas products increased from one to two, further escalating the system's dysfunction.
- 2HBr(g) + Cl₂(g) ⇒2HCl(g) + Br₂(g)
Due to the reactant and product both having an identical number of products in the same state of matter, this is too near to zero to decide.
- 4HCl(g) + O₂(g) ⇒2H2O(g) + 2Cl₂(g)
Due to the reactant and product both having an identical number of products in the same state of matter, this is too near to zero to decide.
- CaCO₃(s) → CaO(s) + CO₂(g)
Due to the formation of one gas products from one solid, this is more than zero. The number of gas products increased from zero to one, further escalating the system's dysfunction.
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