The average resistance force exerted on the diver by the water is 2,000 N
According to the law of conservation of energy, the mechanical energy is constant.
Mechanical energy (EM) is equal to the kinetic energy (Ek) + potential energy (Ep).
In the given problem, the diver comes to rest at 2.96 m below the surface of the water. Hence, at this point, his velocity is zero, so is its kinetic energy. Therefore, according to the law of conservation of energy:
ΔE = - mg (h₂ - h₁)
Where:
m = mass of the diver
g = gravitation due to gravity
h = height
Hence,
ΔE = - 66.9 x 9.8 x (-2.96 - 6.07)
= 5920.25 Joule
This is equivalent to the work done by the resistance force.
Hence,
W = ΔE = F . s
Where:
s = distance under water
Hence,
5920.25 = F x 2.96
F = 5920.25 / 2.96 = 2,000 N
Learn more about energy conservation here:
https://brainly.com/question/27422874
#SPJ4
