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A circle has the equation x^2−8y−6x+y^2=4.

A: What value should be added to each side of the equation to complete the square for the x's?

B: What value should be added to each side of the equation to complete the square for the y's?

C: What is the standard form of the equation?

Select three answer choices: one for question A, one for question B, and one for question C.

A: 3
B: 4
C: (x−3)2+(y−4)2=29
A: 36
B: 16
C: (x−3)2+(y−4)2=16
A: 9
C: (x−3)2+(y−4)2=25
B: 64

Respuesta :

ghanami
Hello here is a solution :
x²-8y-6x+y²=4....(1)
A)
x²-6x = x²-2(3)x+9-9
         = x²-2(3)x+3²-9
x²-6x =(x-3)² -9
B)
y²-8y = y²-2(4)y +4²-16
y²-8y = (y-4)²-16
C)
in (1) :

(x-3)² -9 +(y-4)²-16 = 4
(x-3)² +(y-4)² = 29   ...is the standard form of the equation

   Select answer 1 : 
A: 3
B: 4
C: (x−3)2+(y−4)2=29

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