The right answer is d.telophase meiosis ii.
Meiosis II consists of splitting the chromosomes in half from their point of attachment. This results in four haploid daughter cells.
In the phase of telophase II and cytokinesis (the last step), there is a reformation of the nuclear envelopes at each of the poles as the division furrows progress. It ends with four daughter cells each with a haploid number of chromosomes.
