Respuesta :
This system has one solution. Here are my steps to solving this problem:
y=x+1
2(x+1) - x = 2
2x +2 - x = 2
2x - x + 2 = 2
x + 2 = 2
- 2 - 2
----------------
x = 0
y = 0 + 1
y = 1
I hope this helps you!
y=x+1
2(x+1) - x = 2
2x +2 - x = 2
2x - x + 2 = 2
x + 2 = 2
- 2 - 2
----------------
x = 0
y = 0 + 1
y = 1
I hope this helps you!
Answer:
The system has one solution i.e., (0,1).
Step-by-step explanation:
Given : The system of equations [tex]y=x+1[/tex] and [tex]2y-x=2[/tex]
To find : The system shown has _____ solution(s)?
Solution :
We solve the system of equations by substitution method,
Let [tex]y=x+1[/tex] .....(1)
[tex]2y-x=2[/tex] ......(2)
Substitute the value of y of equation (1) into (2)
[tex]2y-x=2[/tex]
[tex]2(x+1)-x=2[/tex]
[tex]2x+2-x=2[/tex]
[tex]x=0[/tex]
Substitute in equation (1)
[tex]y=x+1[/tex]
[tex]y=0+1[/tex]
[tex]y=1[/tex]
Therefore, The system has one solution i.e., (0,1).
