Can someone lead me through the steps of rewriting the quadratic function in vertex form???
Rewrite the quadratic function in vertex form... then determine the maximum and minimum and the axis of symmetry:
y = -3x^2 + 18x - 2
complete the square to get y=a(x-h)²+k (h,k) is vertex x=h is axis of symmetry if a>0 then the verex is a minimum if a<0 then the vertex is a maximum
so
groupu x terms
y=(-3x²+18x)-3 undistribute -3 y=-3(x²-6x)-3 take 1/2 of the liear coefient then square it -6/2=-3, (-3)²=9 add positve and negative of that inside parentheasees y=-3(x²-6x+9-9)-3 factor perfect squrae y=-3((x-3)²-9)-3 expand/distribute y=-3(x-3)²+27-3 y=-3(x-3)²+24 vertex is (3,24) -3<0 so it is a maximum axis of symmetry is x=3
