Respuesta :
the answer
the general equation of the reaction isÂ
NH4NO3 -------------- N2O Â + Â 2H2OÂ
The molar mass of NH4NO3 is 80.03Â
The mass of NH4NO3 is 160.1 g
 so we can deduce that Â
nNH4NO3 = number of mole of NH4NO3 = 160.1 g / 80.03  =2 moles
by using proportion propertyÂ
NH4NO3 -------------- N2O Â + Â 2H2OÂ
1mole            1mole   2 moles
nNH4NO3 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â nH2O
the number of mole nH2O can be found byÂ
1/ nNH4NO3Â Â = Â 2 / Â Â Â Â Â Â nH2OÂ
      nH2O = 2 x  nNH4NO3 = 2 x 2 = 4 moles
to find the mass, we useÂ
mH2O = 4 moles x  18.01 g /mol = 36 g
the general equation of the reaction isÂ
NH4NO3 -------------- N2O Â + Â 2H2OÂ
The molar mass of NH4NO3 is 80.03Â
The mass of NH4NO3 is 160.1 g
 so we can deduce that Â
nNH4NO3 = number of mole of NH4NO3 = 160.1 g / 80.03  =2 moles
by using proportion propertyÂ
NH4NO3 -------------- N2O Â + Â 2H2OÂ
1mole            1mole   2 moles
nNH4NO3 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â nH2O
the number of mole nH2O can be found byÂ
1/ nNH4NO3Â Â = Â 2 / Â Â Â Â Â Â nH2OÂ
      nH2O = 2 x  nNH4NO3 = 2 x 2 = 4 moles
to find the mass, we useÂ
mH2O = 4 moles x  18.01 g /mol = 36 g