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In order to form a new compound A, one mole of N2H4 loses ten moles of electrons. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in A? (Consider that, there is no change in the oxidation state of hydrogen.)

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Answer:

1 mole of hydrazine contains 2 moles of N and loses 10 moles of electrons. Hence, 1 N atom will lose 5 electrons. Hence, its oxidation number will increase by 5. Hence, the oxidation number of N in compound A will be −2 + 5 = +3.

Explanation:

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