Answer:A is the correct answer to this problem
Explanation:To find the time period of oscillation, we can use the formula:
\[ T = \frac{2π}{ω} \]
Where ω is the angular frequency. For a simple harmonic motion equation of the form \( d²x/dt² + ω²x = 0 \), ω is given by:
\[ ω = \sqrt{\frac{k}{m}} \]
In this case, \( k = 320 \) and \( m = 4 \). So, \( ω = \sqrt{\frac{320}{4}} = \sqrt{80} \).
Thus, the time period \( T = \frac{2π}{\sqrt{80}} \).
So, the correct answer is A. \( \frac{2π}{\sqrt{80}} \) s.
