if an object has a mass of 5.6kg and displaces 1 liter of seawater of 1025kg/m^3, then what is its density?

Respuesta :

To find the density (\( \rho \)) of the object, you would use the formula:

\[ \rho = \frac{m}{V} \]

where \( m \) is the mass of the object, and \( V \) is the volume it displaces.

Given that the mass \( m \) of the object is 5.6 kg and it displaces 1 liter (L) of seawater, we need to convert the volume into cubic meters (m³) since density is typically expressed in kilograms per cubic meter (kg/m³).

1 liter is equivalent to 0.001 cubic meters (1 L = 0.001 m³).

Now, you can calculate the density of the object:

\[ \rho = \frac{m}{V} = \frac{5.6 \ \text{kg}}{0.001 \ \text{m}^3} \]

\[ \rho = \frac{5.6 \ \text{kg}}{0.001 \ \text{m}^3} \]

\[ \rho = 5600 \ \text{kg/m}^3 \]

Thus, the density of the object is 5600 kg/m³.