First, we must know that in order to remove one mole of cadmium ions, we will require two moles of sodium ions. This is visible from the fact that the valence charge of cadmium ions is +2, while for sodium ions it is +1.
Next, we use the equation:
Moles = Molarity * Liters
We know that:
moles of sodium = 2 * moles of cadmium
Now, the moles of cadmium present are:
Moles = 0.499 * 0.0327 = 0.0163
The moles of NaOH required are double this, so:
Moles NaOH = 2 * 0.0163 = 0.0326
Mass = moles * molecular weight
Mass = 0.0326 * 40
Mass = 1.304 grams of NaOH
