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Calculate the number of moles in the 2.00-l volume of air in the lungs of the average person. note that the air is at 37.0ºc (body temperature).

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To answer this item, we assume that the air is an ideal gas such that it follows the equation,

       PV = nRT

The pressure of the lungs of the person should be in equilibrium to that of the surrounding, making it 1 atm. Substituting the known values to the equation,

            n = (1 atm)(2L)/(0.0821 L.atm/mol.K)(37 + 273.15)
                     n = 0.0785 moles

Answer: 0.0785 moles

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