A rectangle has an area of 135 cm2 and a perimeter of 48 cm. what are its dimensions

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kadar2256 kadar2256

09-01-2018
Mathematics

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A rectangle has an area of 135 cm2 and a perimeter of 48 cm. what are its dimensions

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texaschic101 texaschic101 · Answer 1 · 2018-01-09T06:14:39+01:00

P = 2(L + W)
P = 48

48 = 2(L + W)
48/2 = L + W
24 = L +W
24 - L = W

A = L * W
A = 135

135 = L(24 - L)
135 = 24L - L^2
L^2 - 24L + 135 = 0
(L - 9)(L - 15) = 0

L - 9 = 0 24 - L = W
L = 9 24 - 9 = W
15 = W

L - 15 = 0 24 - L = W
L = 15 24 - 15 = W
9 = W

the dimensions : either the length is 9 cm and the width is 15 cm.....or the length is 15 cm and the width is 9 cm.