contestada

what is the recursive rule for this geometric sequence?
2, 1/2, 1/8, 1/32

Answer your answers in the boxes

a =_•an-1

a1=_

Respuesta :

altavistard
Each new member of this sequence is 1/4 times the previous member.  For example, 1/2 = (1/4)(2).

Thus, a(n+1) = (1/4)*a(n), with a(1)=2.
Riia

The given sequece is

[tex] 2 , 1/2, 1/8 , 1/32 [/tex]

And we have to find the recursive formula of this geometric sequence.

First term is,

[tex] a_{1} =2 [/tex]

And the common ratio,

[tex] r = \frac{1/2}{2} = \frac{1}{4} [/tex]

So the recursive formula is

[tex] a_{n} = a_{n-1} * \frac{1}{4} [/tex]

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