Respuesta :

526 L O2 x 1 mol O2 / 22.4 L = 23.5 mol O2

Answer: The correct answer is : 23.5 mol of O2 .

At STP ( Standard Temperature and potential ) 1 mole of gas has 22.4 L of volume .The follow can be expressed as :

[tex] Mole = \frac{given volume in L}{22.4 L } * 1 mol [/tex]

Given volume of O2 gas = 526 L

Plugging value in the formula :

[tex] Mole = \frac{526 L}{22.4 L} * 1 mol [/tex]

Mole of O2 gas at STP = 23.5 mol