Part 1) What is the volume of the prism? [volume of the prism]=H*L*W where L=length of the cube W=wide of the cube H=height of the cube
we know that L= 4 units W=3 units H=5 units [volume of the prism]=5*4*3 [volume of the prism]=60 units³
the answer Part 1) is 60 units³
Part 2) · What would be the dimensions of a new right
rectangular prism that has 20 fewer unit cubes than
the original prism?
original volume=60 units³ new volume=(60-20)--------> 40 units³ remember that [original volume of the prism]=(5*4*3)--------> (5*4)*(2+1) [original volume of the prism]=(5*4*2)+(5*4*1) [original volume of the prism]=40 units³+20 units ³ 40 units³---------> new volume of the prism therefore the dimensions of a new right rectangular prism are-------> (5*4*2)
the answer Part 2) is the new dimensions are L= 4 units W=2 units H=5 units
